PutnamSuperchallengeIntegrals I: Feynman's Trick ShareIntegrals I: Feynman's Trick · Superchallenge problemEvaluate ∑n=1∞1n 2n\displaystyle\sum_{n=1}^\infty \frac{1}{n\,2^n}n=1∑∞n2n1. Express your answer as a logarithm.Check Show answer Walk through it step by step Practice more like this Review this concept