PutnamSuperchallengeIntegrals I: Feynman's Trick ShareIntegrals I: Feynman's Trick · Superchallenge problemEvaluate limn→∞13+23+⋯+n3n4\displaystyle\lim_{n\to\infty} \frac{1^3 + 2^3 + \cdots + n^3}{n^4}n→∞limn413+23+⋯+n3.Check Show answer Walk through it step by step Practice more like this Review this concept