PutnamSuperchallengeIntegrals I: Feynman's Trick ShareIntegrals I: Feynman's Trick · Superchallenge problemEvaluate ∑n=1∞1n(n+3)\displaystyle\sum_{n=1}^\infty \frac{1}{n(n+3)}n=1∑∞n(n+3)1.Check Show answer Walk through it step by step Practice more like this Review this concept