PutnamSuperchallengeIntegrals I: Feynman's Trick ShareIntegrals I: Feynman's Trick · Superchallenge problemA polynomial PPP of degree 333 satisfies P(k)=1kP(k) = \dfrac1kP(k)=k1 for k=1,2,3,4k = 1, 2, 3, 4k=1,2,3,4. Compute P(5)P(5)P(5).Check Show answer Walk through it step by step Practice more like this Review this concept