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PutnamSuperchallengeIntegrals I: Feynman's Trick

Integrals I: Feynman's Trick · Superchallenge problem

A polynomial PP of degree 33 satisfies P(k)=1kP(k) = \dfrac1k for k=1,2,3,4k = 1, 2, 3, 4. Compute P(5)P(5).