PutnamSuperchallengeIntegrals I: Feynman's Trick ShareIntegrals I: Feynman's Trick · Superchallenge problemEvaluate limn→∞1n∑k=1nkn\displaystyle\lim_{n\to\infty} \frac1n\sum_{k=1}^n \sqrt{\frac{k}{n}}n→∞limn1k=1∑nnk.Check Show answer Walk through it step by step Practice more like this Review this concept