PutnamSuperchallengeIntegrals I: Feynman's Trick ShareIntegrals I: Feynman's Trick · Superchallenge problemLet fff be continuous on [0,1][0,1][0,1] with ∫01f(x) dx=2\displaystyle\int_0^1 f(x)\,dx = 2∫01f(x)dx=2. Find the minimum possible value of ∫01f(x)2 dx\displaystyle\int_0^1 f(x)^2\,dx∫01f(x)2dx.Check Show answer Walk through it step by step Practice more like this Review this concept