PutnamSuperchallengeIntegrals I: Feynman's Trick ShareIntegrals I: Feynman's Trick · Superchallenge problemLet x,y>0x, y > 0x,y>0 with x+y=1x + y = 1x+y=1. Find the minimum value of 1x+4y\dfrac1x + \dfrac4yx1+y4.Check Show answer Walk through it step by step Practice more like this Review this concept