PutnamSuperchallengeIntegrals I: Feynman's Trick ShareIntegrals I: Feynman's Trick · Superchallenge problemLet f(x)=x+1x−1f(x) = \dfrac{x+1}{x-1}f(x)=x−1x+1 for x≠1x \ne 1x=1. Compute f2025(3)f^{2025}(3)f2025(3), where fnf^{n}fn denotes fff composed with itself nnn times.Check Show answer Walk through it step by step Practice more like this Review this concept