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PutnamSuperchallengeIntegrals I: Feynman's Trick

Integrals I: Feynman's Trick · Superchallenge problem

A function f:Q→Qf:\mathbb Q\to\mathbb Q satisfies f(x+y)=f(x)+f(y)f(x+y) = f(x) + f(y) for all rationals x,yx, y, and f(3)=7f(3) = 7. Compute f ⁣(92)f\!\left(\tfrac92\right).