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PutnamSuperchallengeIntegrals I: Feynman's Trick

Integrals I: Feynman's Trick · Superchallenge problem

A function satisfies f(x+1)=1+f(x)1−f(x)f(x+1) = \dfrac{1 + f(x)}{1 - f(x)} for all xx where both sides are defined, and f(0)=2f(0) = 2. Compute f(2024)f(2024).