PutnamSuperchallengeIntegrals I: Feynman's Trick ShareIntegrals I: Feynman's Trick · Superchallenge problemA function f:R∖{0}→Rf:\mathbb R\setminus\{0\}\to\mathbb Rf:R∖{0}→R satisfies f(x)+2f (1x)=3xf(x) + 2f\!\left(\tfrac1x\right) = 3xf(x)+2f(x1)=3x for all x≠0x \ne 0x=0. Compute f(2)f(2)f(2).Check Show answer Walk through it step by step Practice more like this Review this concept