PutnamSuperchallengeIntegrals I: Feynman's Trick ShareIntegrals I: Feynman's Trick · Superchallenge problemCompute limx→0sinx−xx3\displaystyle\lim_{x\to0}\frac{\sin x - x}{x^3}x→0limx3sinx−x. Express your answer as a common fraction.Check Show answer Walk through it step by step Practice more like this Review this concept