PutnamSuperchallengeIntegrals I: Feynman's Trick ShareIntegrals I: Feynman's Trick · Superchallenge problemEvaluate ∑k=12025⌊k⌋\displaystyle\sum_{k=1}^{2025} \left\lfloor\sqrt{k}\right\rfloork=1∑2025⌊k⌋.Check Show answer Walk through it step by step Practice more like this Review this concept