PutnamSuperchallengeIntegrals I: Feynman's Trick ShareIntegrals I: Feynman's Trick · Superchallenge problemDefine a0=3a_0 = 3a0=3 and an+1=an2−2a_{n+1} = a_n^2 - 2an+1=an2−2. Evaluate ∑n=0∞1a0a1⋯an\displaystyle\sum_{n=0}^{\infty} \frac{1}{a_0a_1\cdots a_n}n=0∑∞a0a1⋯an1. Express your answer in simplest radical form.Check Show answer Walk through it step by step Practice more like this Review this concept