PutnamSuperchallengeIntegrals I: Feynman's Trick ShareIntegrals I: Feynman's Trick · Superchallenge problemEvaluate ∑k=1∞1k(k+1)(k+2)(k+3)\displaystyle\sum_{k=1}^{\infty} \frac{1}{k(k+1)(k+2)(k+3)}k=1∑∞k(k+1)(k+2)(k+3)1. Express your answer as a common fraction.Check Show answer Walk through it step by step Practice more like this Review this concept