PutnamSuperchallengeIntegrals I: Feynman's Trick ShareIntegrals I: Feynman's Trick · Superchallenge problemEvaluate ∑n=120241n+n+1\displaystyle\sum_{n=1}^{2024} \frac{1}{\sqrt{n} + \sqrt{n+1}}n=1∑2024n+n+11.Check Show answer Walk through it step by step Practice more like this Review this concept