PutnamSuperchallengeIntegrals I: Feynman's Trick ShareIntegrals I: Feynman's Trick · Superchallenge problemA function f:Q→Qf:\mathbb Q\to\mathbb Qf:Q→Q satisfies f(x+y)=f(x)+f(y)f(x + y) = f(x) + f(y)f(x+y)=f(x)+f(y) for all rationals and f(1)=7f(1) = 7f(1)=7. Compute f (37)f\!\left(\tfrac37\right)f(73).Check Show answer Walk through it step by step Practice more like this Review this concept