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PutnamSuperchallengeIntegrals I: Feynman's Trick

Integrals I: Feynman's Trick · Superchallenge problem

A function f:Q→Qf:\mathbb Q\to\mathbb Q satisfies f(x+y)=f(x)+f(y)f(x + y) = f(x) + f(y) for all rationals and f(1)=7f(1) = 7. Compute f ⁣(37)f\!\left(\tfrac37\right).