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Differential EquationsChallengeFrobenius & Special Functions

Frobenius & Special Functions · Challenge problem

The Legendre polynomial P2(x)=3x2−12P_2(x) = \tfrac{3x^2 - 1}{2} solves Legendre's equation with n=2n = 2. Compute P2(2)P_2(2). Express your answer as a common fraction.