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Differential EquationsHardExistence, Uniqueness & Bifurcations

Existence, Uniqueness & Bifurcations · Hard problem

The IVP y′=y2/3y' = y^{2/3}, y(0)=0y(0) = 0 famously has MORE than one solution: y≡0y \equiv 0 works, and so does y=(x3)3y = \left(\tfrac{x}{3}\right)^3. Evaluate the second solution at x=3x = 3.