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Differential EquationsHardBoundary Values & Fourier Series

Boundary Values & Fourier Series · Hard problem

The Fourier sine series of f(x)=1f(x) = 1 on (0,π)(0, \pi) is ∑bnsin⁡nx\sum b_n\sin nx with bn=2π∫0πsin⁡nx dxb_n = \dfrac{2}{\pi}\displaystyle\int_0^\pi \sin nx\,dx. Compute π b1\pi\,b_1.