ChallengeMedium ShareChallenge · Medium problemEvaluate ∑k=16csc2kπ7=∑k=161sin2(kπ/7)\displaystyle\sum_{k=1}^{6}\csc^2\frac{k\pi}{7}=\sum_{k=1}^{6}\frac{1}{\sin^2(k\pi/7)}k=1∑6csc27kπ=k=1∑6sin2(kπ/7)1.Check Show answer Walk through it step by step Practice more like this