ChallengeMedium ShareChallenge · Medium problemIn △ABC\triangle ABC△ABC, AB=13AB=13AB=13, BC=14BC=14BC=14, and CA=15CA=15CA=15. The bisector of ∠A\angle A∠A meets BC‾\overline{BC}BC at DDD. Find the length ADADAD.A3653\dfrac{3\sqrt{65}}{3}3365B3652\dfrac{3\sqrt{65}}{2}2365C2365\dfrac{2}{3\sqrt{65}}3652D6652\dfrac{6\sqrt{65}}{2}2665Check Show answer Walk through it step by step Practice more like this