CalculusChallenge ShareCalculus · Challenge problemCompute the integer nearest to 100ln2100\ln 2100ln2, given ln2=1−12+13−14+⋯\ln 2 = 1 - \tfrac12 + \tfrac13 - \tfrac14 + \cdotsln2=1−21+31−41+⋯.Check Show answer Walk through it step by step Practice more like this