CalculusHard ShareCalculus · Hard problemSolve dydx=xy2\dfrac{dy}{dx}=xy^2dxdy=xy2 with y(0)=1y(0)=1y(0)=1.A22−x3\dfrac{2}{2-x^3}2−x32B22−x2\dfrac{2}{2-x^2}2−x22C2−x22\dfrac{2-x^2}{2}22−x2D22−x3\dfrac{2}{2-x^{3}}2−x32Check Show answer Walk through it step by step Practice more like this