CalculusHard ShareCalculus · Hard problemEvaluate ∫(6x2−4x) dx\displaystyle\int (6x^2-4x)\,dx∫(6x2−4x)dx.A2x3+2x2+C2x^3+2x^2+C2x3+2x2+CB2x3−2x2+C2x^3-2x^2+C2x3−2x2+CC2x4−2x2+C2x^{4}-2x^2+C2x4−2x2+CD2x3−2x3+C2x^3-2x^3+C2x3−2x3+CCheck Show answer Walk through it step by step Practice more like this