CalculusHard ShareCalculus · Hard problemDifferentiate f(x)=2x+1x−3f(x)=\dfrac{2x+1}{x-3}f(x)=x−32x+1.A(x−3)2−7\dfrac{(x-3)^2}{-7}−7(x−3)2B−7(x−3)3\dfrac{-7}{(x-3)^{3}}(x−3)3−7C−7(x−3)2\dfrac{-7}{(x-3)^2}(x−3)2−7D−7(x−3)3\dfrac{-7}{(x-3)^3}(x−3)3−7Check Show answer Walk through it step by step Practice more like this