CalculusHardDifferential Equations ShareDifferential Equations · Hard problemSolve the IVP (x2+1)dydx=xy(x^2+1)\dfrac{dy}{dx}=xy(x2+1)dxdy=xy, y(0)=3y(0)=3y(0)=3.Ay=3x2+2y=3\sqrt{x^2+2}y=3x2+2By=3x2+1y=3\sqrt{x^2+1}y=3x2+1Cy=6x2+1y=6\sqrt{x^2+1}y=6x2+1Dy=3x3+1y=3\sqrt{x^{3}+1}y=3x3+1Check Show answer Walk through it step by step Practice more like this Review this concept