CalculusHardDifferential Equations ShareDifferential Equations · Hard problemSolve the IVP dydx=2xy+1\dfrac{dy}{dx}=\dfrac{2x}{y+1}dxdy=y+12x, y(0)=1y(0)=1y(0)=1, giving yyy explicitly (choose the branch through the initial point).Ay=−1+2x2+5y=-1+\sqrt{2x^2+5}y=−1+2x2+5By=−1+2x2+4y=-1+\sqrt{2x^2+4}y=−1+2x2+4Cy=−1+2x3+4y=-1+\sqrt{2x^{3}+4}y=−1+2x3+4Dy=1+2x2+4y=1+\sqrt{2x^2+4}y=1+2x2+4Check Show answer Walk through it step by step Practice more like this Review this concept