CalculusMediumDifferential Equations ShareDifferential Equations · Medium problemSolve the IVP dydx=xy2\dfrac{dy}{dx}=xy^2dxdy=xy2, y(0)=1y(0)=1y(0)=1.Ay=22−x2y=\dfrac{2}{2-x^2}y=2−x22By=2−x22y=\dfrac{2-x^2}{2}y=22−x2Cy=22−x3y=\dfrac{2}{2-x^{3}}y=2−x32Dy=22−x3y=\dfrac{2}{2-x^3}y=2−x32Check Show answer Walk through it step by step Practice more like this Review this concept