CalculusSuperchallengeDifferential Equations ShareDifferential Equations · Superchallenge problemSolve (1+x2)dydx=1+y2(1+x^2)\dfrac{dy}{dx}=1+y^2(1+x2)dxdy=1+y2 with y(0)=1y(0)=1y(0)=1; express yyy as a rational function of xxx and state where it is valid.Ay=1+x2−xy=\dfrac{1+x}{2-x}y=2−x1+xBy=2+x1−xy=\dfrac{2+x}{1-x}y=1−x2+xCy=1−x1+xy=\dfrac{1-x}{1+x}y=1+x1−xDy=1+x1−xy=\dfrac{1+x}{1-x}y=1−x1+xCheck Show answer Walk through it step by step Practice more like this Review this concept