CalculusChallengeDifferential Equations ShareDifferential Equations · Challenge problemSolve dydx=3x2+4x+22(y−1)\dfrac{dy}{dx}=\dfrac{3x^2+4x+2}{2(y-1)}dxdy=2(y−1)3x2+4x+2 with y(0)=−1y(0)=-1y(0)=−1, choosing the branch consistent with the initial condition.Ay=1−x3+2x2+2x+4y=1-\sqrt{x^3+2x^2+2x+4}y=1−x3+2x2+2x+4By=1−x3+2x2+2x+5y=1-\sqrt{x^3+2x^2+2x+5}y=1−x3+2x2+2x+5Cy=1−x4+2x2+2x+4y=1-\sqrt{x^{4}+2x^2+2x+4}y=1−x4+2x2+2x+4Dy=1+x3+2x2+2x+4y=1+\sqrt{x^3+2x^2+2x+4}y=1+x3+2x2+2x+4Check Show answer Walk through it step by step Practice more like this Review this concept