CalculusHard ShareCalculus · Hard problemFind ∫cos2xcosx−sinx dx\displaystyle\int \frac{\cos 2x}{\cos x-\sin x}\,dx∫cosx−sinxcos2xdx (factor the numerator first).Asinx+cosx+C\sin x+\cos x+Csinx+cosx+CB−sinx−cosx+C-\sin x-\cos x+C−sinx−cosx+CCsinx−cosx+C\sin x-\cos x+Csinx−cosx+CDsinx+cosx−C\sin x+\cos x-Csinx+cosx−CCheck Show answer Walk through it step by step Practice more like this