CalculusHard ShareCalculus · Hard problemEvaluate ∫232x−1x2−x dx\displaystyle\int_2^{3}\frac{2x-1}{x^2-x}\,dx∫23x2−x2x−1dx.Aln4\ln 4ln4Bln6\ln 6ln6C−ln3-\ln 3−ln3Dln3\ln 3ln3Check Show answer Walk through it step by step Practice more like this