CalculusHard ShareCalculus · Hard problemFind ∫(3ex−2secxtanx+41+x2) dx\displaystyle\int \Big(3e^{x}-2\sec x\tan x+\frac{4}{1+x^2}\Big)\,dx∫(3ex−2secxtanx+1+x24)dx.A3ex−2secx+4arctanx+C3e^{x}-2\sec x+4\arctan x+C3ex−2secx+4arctanx+CB3ex+2secx+4arctanx+C3e^{x}+2\sec x+4\arctan x+C3ex+2secx+4arctanx+CC6ex−2secx+4arctanx+C6e^{x}-2\sec x+4\arctan x+C6ex−2secx+4arctanx+CD3ex−2secx+5arctanx+C3e^{x}-2\sec x+5\arctan x+C3ex−2secx+5arctanx+CCheck Show answer Walk through it step by step Practice more like this