CalculusEasy ShareCalculus · Easy problemEvaluate ∫012x (x2+1)3 dx\displaystyle\int_0^1 2x\,(x^2+1)^3\,dx∫012x(x2+1)3dx by changing the limits (u=x2+1u=x^2+1u=x2+1).Check Show answer Walk through it step by step Practice more like this