CalculusHard ShareCalculus · Hard problemFind d2ydx2\dfrac{d^2y}{dx^2}dx2d2y if x3+y3=8x^3+y^3=8x3+y3=8, simplified using the original equation.A−16xy6-\dfrac{16x}{y^6}−y616xB−y516x-\dfrac{y^5}{16x}−16xy5C−16xy5-\dfrac{16x}{y^5}−y516xD−16xy6-\dfrac{16x}{y^{6}}−y616xCheck Show answer Walk through it step by step Practice more like this