CalculusEasy ShareCalculus · Easy problemFind dydx\dfrac{dy}{dx}dxdy if y=e2xxy=\dfrac{e^{2x}}{x}y=xe2x.Ae2x(2x−1)x3\dfrac{e^{2x}(2x-1)}{x^3}x3e2x(2x−1)Be2x(2x−1)x2\dfrac{e^{2x}(2x-1)}{x^2}x2e2x(2x−1)Cx2e2x(2x−1)\dfrac{x^2}{e^{2x}(2x-1)}e2x(2x−1)x2De4x(2x−1)x2\dfrac{e^{4x}(2x-1)}{x^2}x2e4x(2x−1)Check Show answer Walk through it step by step Practice more like this