CalculusEasy ShareCalculus · Easy problemFind dydx\dfrac{dy}{dx}dxdy if y=x2cos(3x)y=x^2\cos(3x)y=x2cos(3x).A2xcos(3x)+3x2sin(3x)2x\cos(3x)+3x^2\sin(3x)2xcos(3x)+3x2sin(3x)B2xcos(3x)−3x3sin(3x)2x\cos(3x)-3x^{3}\sin(3x)2xcos(3x)−3x3sin(3x)C2xcos(3x)−3x2sin(3x)2x\cos(3x)-3x^2\sin(3x)2xcos(3x)−3x2sin(3x)D2xcos(3x)−3x2sin(4x)2x\cos(3x)-3x^2\sin(4x)2xcos(3x)−3x2sin(4x)Check Show answer Walk through it step by step Practice more like this