CalculusSuperchallenge ShareCalculus · Superchallenge problemAssuming xy=yxx^y=y^xxy=yx defines yyy as a differentiable function of xxx, find dydx\dfrac{dy}{dx}dxdy in terms of xxx and yyy.Ax(ylnx−x)y(xlny−y)\dfrac{x(y\ln x-x)}{y(x\ln y-y)}y(xlny−y)x(ylnx−x)By(xlny−y)x(ylnx−x)\dfrac{y(x\ln y-y)}{x(y\ln x-x)}x(ylnx−x)y(xlny−y)Cy(xlny+y)x(ylnx+x)\dfrac{y(x\ln y+y)}{x(y\ln x+x)}x(ylnx+x)y(xlny+y)D−y(xlny−y)x(ylnx−x)-\dfrac{y(x\ln y-y)}{x(y\ln x-x)}−x(ylnx−x)y(xlny−y)Check Show answer Walk through it step by step Practice more like this