CalculusMediumThe Derivative ShareThe Derivative · Medium problemFind ddx[sinxcosx]\dfrac{d}{dx}\big[\sin x\cos x\big]dxd[sinxcosx] using the product rule.Acos2x−sin3x\cos^{2}x-\sin^{3}xcos2x−sin3xBcos2x−sin2x\cos^{2}x-\sin^{2}xcos2x−sin2xCcos3x−sin2x\cos^{3}x-\sin^{2}xcos3x−sin2xDcos2x+sin2x\cos^{2}x+\sin^{2}xcos2x+sin2xCheck Show answer Walk through it step by step Practice more like this Review this concept