CalculusEasyThe Derivative ShareThe Derivative · Easy problemUse the quotient rule to find ddx [exx]\dfrac{d}{dx}\!\left[\dfrac{e^{x}}{x}\right]dxd[xex].Ax2ex(x−1)\dfrac{x^{2}}{e^{x}(x-1)}ex(x−1)x2Bex(x−1)x2\dfrac{e^{x}(x-1)}{x^{2}}x2ex(x−1)Cex(x−2)x2\dfrac{e^{x}(x-2)}{x^{2}}x2ex(x−2)Dex(x−1)x3\dfrac{e^{x}(x-1)}{x^{3}}x3ex(x−1)Check Show answer Walk through it step by step Practice more like this Review this concept