CalculusEasyThe Derivative ShareThe Derivative · Easy problemUse the quotient rule to find ddx [xx+1]\dfrac{d}{dx}\!\left[\dfrac{x}{x+1}\right]dxd[x+1x].A(x+1)21\dfrac{(x+1)^{2}}{1}1(x+1)2B2(x+1)2\dfrac{2}{(x+1)^{2}}(x+1)22C1(x+1)2\dfrac{1}{(x+1)^{2}}(x+1)21D1(x+1)3\dfrac{1}{(x+1)^{3}}(x+1)31Check Show answer Walk through it step by step Practice more like this Review this concept