CalculusEasyThe Derivative ShareThe Derivative · Easy problemFind ddx[3sinx−2cosx]\dfrac{d}{dx}\big[3\sin x-2\cos x\big]dxd[3sinx−2cosx].A3cosx−2sinx3\cos x-2\sin x3cosx−2sinxB3cosx+3sinx3\cos x+3\sin x3cosx+3sinxC3cosx+2sinx3\cos x+2\sin x3cosx+2sinxD6cosx+2sinx6\cos x+2\sin x6cosx+2sinxCheck Show answer Walk through it step by step Practice more like this Review this concept