Infinite Sequences and Series · Easy problem

$x+\dfrac{x^3}{6}+\dfrac{x^5}{120}$

$x-\dfrac{x^3}{6}+\dfrac{x^5}{121}$

$x-\dfrac{x^3}{6}+\dfrac{x^5}{120}$

$x-\dfrac{6}{x^3}+\dfrac{x^5}{120}$