CalculusHardLimits and Continuity ShareLimits and Continuity · Hard problemFind the value of aaa that makes fff continuous everywhere:f(x)={x2−9x−3,x≠3a,x=3.f(x)=\begin{cases}\dfrac{x^2-9}{x-3}, & x\neq 3\\[2mm] a, & x=3.\end{cases}f(x)=⎩⎨⎧x−3x2−9,a,x=3x=3.Check Show answer Walk through it step by step Practice more like this Review this concept