CalculusHardChain, Implicit and Inverse Differentiation ShareChain, Implicit and Inverse Differentiation · Hard problemLet y=ln(x2+1)y = \ln(x^2 + 1)y=ln(x2+1). Find dydx\dfrac{dy}{dx}dxdy at x=1x = 1x=1.Check Show answer Walk through it step by step Practice more like this Review this concept