Algebra 2Medium ShareAlgebra 2 · Medium problemV=13πr2hV = \dfrac{1}{3}\pi r^2 hV=31πr2h; solve for hhh.A3Vπr2\dfrac{3V}{\pi r^2}πr23VB3Vπr3\dfrac{3V}{\pi r^3}πr33VCπr23V\dfrac{\pi r^2}{3V}3Vπr2D3Vπr3\dfrac{3V}{\pi r^{3}}πr33VCheck Show answer Walk through it step by step Practice more like this