Algebra 1SuperchallengeSystems of Equations ShareSystems of Equations · Superchallenge problemClear the fractions, then solve {x6+y4=2x3=y2\begin{cases} \dfrac{x}{6}+\dfrac{y}{4}=2 \\[6pt] \dfrac{x}{3}=\dfrac{y}{2} \end{cases}⎩⎨⎧6x+4y=23x=2yA(4,6)(4, 6)(4,6)B(6,4)(6,4)(6,4)C(−6,4)(-6, 4)(−6,4)D(6,−4)(6, -4)(6,−4)Check Show answer Walk through it step by step Practice more like this Review this concept