Algebra 1Superchallenge ShareAlgebra 1 · Superchallenge problemSolve xy−3x=2y+5 \;xy - 3x = 2y + 5\;xy−3x=2y+5 for x\mathbf{x}x.Ax=2y+5y−4x = \dfrac{2y + 5}{y - 4}x=y−42y+5Bx=2y+5y−3x = \dfrac{2y + 5}{y - 3}x=y−32y+5Cx=4y+5y−3x = \dfrac{4y + 5}{y - 3}x=y−34y+5Dx=y−32y+5x = \dfrac{y - 3}{2y + 5}x=2y+5y−3Check Show answer Walk through it step by step Practice more like this