Algebra 1Challenge ShareAlgebra 1 · Challenge problemSolve A=h(b1+b2)2 \;A = \dfrac{h(b_1 + b_2)}{2}\;A=2h(b1+b2) for b1\mathbf{b_1}b1.Ab1=h2A−hb2b_1 = \dfrac{h}{2A - h b_2}b1=2A−hb2hBb1=2A−hb2hb_1 = \dfrac{2A - h b_2}{h}b1=h2A−hb2Cb1=4A−hb2hb_1 = \dfrac{4A - h b_2}{h}b1=h4A−hb2Db1=3A−hb2hb_1 = \dfrac{3A - h b_2}{h}b1=h3A−hb2Check Show answer Walk through it step by step Practice more like this